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3/4(x-8)=1/2(2x+4)
We move all terms to the left:
3/4(x-8)-(1/2(2x+4))=0
Domain of the equation: 4(x-8)!=0
x∈R
Domain of the equation: 2(2x+4))!=0We calculate fractions
x∈R
(6x2/(4(x-8)*2(2x+4)))+(-4xx/(4(x-8)*2(2x+4)))=0
We calculate terms in parentheses: +(6x2/(4(x-8)*2(2x+4))), so:
6x2/(4(x-8)*2(2x+4))
We multiply all the terms by the denominator
6x2
We add all the numbers together, and all the variables
6x^2
Back to the equation:
+(6x^2)
We calculate terms in parentheses: +(-4xx/(4(x-8)*2(2x+4))), so:We get rid of parentheses
-4xx/(4(x-8)*2(2x+4))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
6x^2-4xx=0
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