3/4(z-1)+2(1-z)=5

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Solution for 3/4(z-1)+2(1-z)=5 equation: 



3/4(z-1)+2(1-z)=5

We move all terms to the left:

3/4(z-1)+2(1-z)-(5)=0



Domain of the equation: 4(z-1)!=0

z∈R



We add all the numbers together, and all the variables

3/4(z-1)+2(-1z+1)-5=0

We multiply parentheses

3/4(z-1)-2z+2-5=0

We multiply all the terms by the denominator


-2z*4(z-1)+2*4(z-1)-5*4(z-1)+3=0

Wy multiply elements

-8z^2(z+8z(z-20z(z+3=0

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