3/4+2/3(s+2t)+s

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Solution for 3/4+2/3(s+2t)+s equation: 


x in (-oo:+oo)

(2/3)*(s+2*t)+s+3/4 = 0

2/3*(s+2*t)+s+3/4 = 0

(2/3*4*(s+2*t))/4+(4*s)/4+3/4 = 0

2/3*4*(s+2*t)+4*s+3 = 0

20/3*s+16/3*t+3 = 0

(20/3*s+16/3*t+3)/4 = 0

(20/3*s+16/3*t+3)/4 = 0 // * 4

20/3*s+16/3*t+3 = 0

x belongs to the empty set

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