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3/4-1/2(x-8)=-2/5(2x+5)+3x
We move all terms to the left:
3/4-1/2(x-8)-(-2/5(2x+5)+3x)=0
Domain of the equation: 2(x-8)!=0
x∈R
Domain of the equation: 5(2x+5)+3x)!=0We calculate fractions
x∈R
(-60x^2-40x)/(2(x-8)*5(2x+5)+3x)*4)+(-(-2*2(x-8)*4)/(2(x-8)*5(2x+5)+3x)*4)+(30x^2(+4x))/(2(x-8)*5(2x+5)+3x)*4)=0
We calculate terms in parentheses: -(-2*2(x-8)*4)/(2(x-8)*5(2x+5)+3x)*4)+(30x^2(+4x))/(2(x-8)*5(2x+5), so:
-2*2(x-8)*4)/(2(x-8)*5(2x+5)+3x)*4)+(30x^2(+4x))/(2(x-8)*5(2x+5
We calculate fractions
We do not support expression: x^3(x
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