3/4=x+5/x-2

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Solution for 3/4=x+5/x-2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/4 = x+5/x-2 // - x+5/x-2

3/4-x-(5/x)+2 = 0

3/4-x-5*x^-1+2 = 0

11/4*x^0-1*x^1-5*x^-1 = 0

(11/4*x^1-1*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(11/4*x^1-1*x^2-5*x^0) = 0

x^1

(11/4)*x-x^2-5 = 0

(11/4)*x-x^2-5 = 0

DELTA = (11/4)^2-(-5*(-1)*4)

DELTA = -199/16

DELTA < 0

x in { } 

x belongs to the empty set

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