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3/4a-1/6=2/3a
We move all terms to the left:
3/4a-1/6-(2/3a)=0
Domain of the equation: 4a!=0
a!=0/4
a!=0
a∈R
Domain of the equation: 3a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
3/4a-(+2/3a)-1/6=0
We get rid of parentheses
3/4a-2/3a-1/6=0
We calculate fractions
(-36a^2)/432a^2+324a/432a^2+(-288a)/432a^2=0
We multiply all the terms by the denominator
(-36a^2)+324a+(-288a)=0
We get rid of parentheses
-36a^2+324a-288a=0
We add all the numbers together, and all the variables
-36a^2+36a=0
a = -36; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-36)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-36}=\frac{-72}{-72} =1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-36}=\frac{0}{-72} =0 $
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