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3/4a-5=1/2a+2
We move all terms to the left:
3/4a-5-(1/2a+2)=0
Domain of the equation: 4a!=0
a!=0/4
a!=0
a∈R
Domain of the equation: 2a+2)!=0We get rid of parentheses
a∈R
3/4a-1/2a-2-5=0
We calculate fractions
6a/8a^2+(-4a)/8a^2-2-5=0
We add all the numbers together, and all the variables
6a/8a^2+(-4a)/8a^2-7=0
We multiply all the terms by the denominator
6a+(-4a)-7*8a^2=0
Wy multiply elements
-56a^2+6a+(-4a)=0
We get rid of parentheses
-56a^2+6a-4a=0
We add all the numbers together, and all the variables
-56a^2+2a=0
a = -56; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-56)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-56}=\frac{-4}{-112} =1/28 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-56}=\frac{0}{-112} =0 $
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