3/4b+3=6(-b+3)

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Solution for 3/4b+3=6(-b+3) equation: 



3/4b+3=6(-b+3)

We move all terms to the left:

3/4b+3-(6(-b+3))=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



We add all the numbers together, and all the variables

3/4b-(6(-1b+3))+3=0

We multiply all the terms by the denominator


-((6(-1b+3)))*4b+3*4b+3=0

Wy multiply elements

-((6(-1b+3)))*4b+12b+3=0

We add all the numbers together, and all the variables

12b-((6(-1b+3)))*4b+3=0

We move all terms containing b to the left, all other terms to the right

12b-((6(-1b+3)))*4b=-3

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