3/4b+6+1/2b=15+26

Solution for 3/4b+6+1/2b=15+26 equation:

3/4b+6+1/2b=15+26

We move all terms to the left:

3/4b+6+1/2b-(15+26)=0


Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

3/4b+1/2b+6-41=0

We add all the numbers together, and all the variables

3/4b+1/2b-35=0

We calculate fractions


6b/8b^2+4b/8b^2-35=0

We multiply all the terms by the denominator


6b+4b-35*8b^2=0

We add all the numbers together, and all the variables

10b-35*8b^2=0

Wy multiply elements

-280b^2+10b=0

a = -280; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-280)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-280}=\frac{-20}{-560}
=1/28
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-280}=\frac{0}{-560}
=0
$