3/4c+1/2c=2/9

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Solution for 3/4c+1/2c=2/9 equation:



3/4c+1/2c=2/9
We move all terms to the left:
3/4c+1/2c-(2/9)=0
Domain of the equation: 4c!=0
c!=0/4
c!=0
c∈R
Domain of the equation: 2c!=0
c!=0/2
c!=0
c∈R
We add all the numbers together, and all the variables
3/4c+1/2c-(+2/9)=0
We get rid of parentheses
3/4c+1/2c-2/9=0
We calculate fractions
(-32c^2)/648c^2+486c/648c^2+324c/648c^2=0
We multiply all the terms by the denominator
(-32c^2)+486c+324c=0
We add all the numbers together, and all the variables
(-32c^2)+810c=0
We get rid of parentheses
-32c^2+810c=0
a = -32; b = 810; c = 0;
Δ = b2-4ac
Δ = 8102-4·(-32)·0
Δ = 656100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{656100}=810$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(810)-810}{2*-32}=\frac{-1620}{-64} =25+5/16 $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(810)+810}{2*-32}=\frac{0}{-64} =0 $

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