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3/4c+1/3c=1/7
We move all terms to the left:
3/4c+1/3c-(1/7)=0
Domain of the equation: 4c!=0
c!=0/4
c!=0
c∈R
Domain of the equation: 3c!=0We add all the numbers together, and all the variables
c!=0/3
c!=0
c∈R
3/4c+1/3c-(+1/7)=0
We get rid of parentheses
3/4c+1/3c-1/7=0
We calculate fractions
(-36c^2)/588c^2+441c/588c^2+196c/588c^2=0
We multiply all the terms by the denominator
(-36c^2)+441c+196c=0
We add all the numbers together, and all the variables
(-36c^2)+637c=0
We get rid of parentheses
-36c^2+637c=0
a = -36; b = 637; c = 0;
Δ = b2-4ac
Δ = 6372-4·(-36)·0
Δ = 405769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{405769}=637$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(637)-637}{2*-36}=\frac{-1274}{-72} =17+25/36 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(637)+637}{2*-36}=\frac{0}{-72} =0 $
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