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3/4e-13=1/2e-15
We move all terms to the left:
3/4e-13-(1/2e-15)=0
Domain of the equation: 4e!=0
e!=0/4
e!=0
e∈R
Domain of the equation: 2e-15)!=0We get rid of parentheses
e∈R
3/4e-1/2e+15-13=0
We calculate fractions
6e/8e^2+(-4e)/8e^2+15-13=0
We add all the numbers together, and all the variables
6e/8e^2+(-4e)/8e^2+2=0
We multiply all the terms by the denominator
6e+(-4e)+2*8e^2=0
Wy multiply elements
16e^2+6e+(-4e)=0
We get rid of parentheses
16e^2+6e-4e=0
We add all the numbers together, and all the variables
16e^2+2e=0
a = 16; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·16·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*16}=\frac{-4}{32} =-1/8 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*16}=\frac{0}{32} =0 $
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