3/4e-3/8e=-18

Solution for 3/4e-3/8e=-18 equation:

3/4e-3/8e=-18

We move all terms to the left:

3/4e-3/8e-(-18)=0


Domain of the equation: 4e!=0

e!=0/4

e!=0

e∈R



Domain of the equation: 8e!=0

e!=0/8

e!=0

e∈R


We add all the numbers together, and all the variables

3/4e-3/8e+18=0

We calculate fractions


24e/32e^2+(-12e)/32e^2+18=0

We multiply all the terms by the denominator


24e+(-12e)+18*32e^2=0

Wy multiply elements

576e^2+24e+(-12e)=0

We get rid of parentheses

576e^2+24e-12e=0

We add all the numbers together, and all the variables

576e^2+12e=0

a = 576; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·576·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*576}=\frac{-24}{1152}
=-1/48
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*576}=\frac{0}{1152}
=0
$