3/4f+2=3-1/2f

Solution for 3/4f+2=3-1/2f equation:

3/4f+2=3-1/2f

We move all terms to the left:

3/4f+2-(3-1/2f)=0


Domain of the equation: 4f!=0

f!=0/4

f!=0

f∈R



Domain of the equation: 2f)!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

3/4f-(-1/2f+3)+2=0

We get rid of parentheses

3/4f+1/2f-3+2=0

We calculate fractions


6f/8f^2+4f/8f^2-3+2=0

We add all the numbers together, and all the variables

6f/8f^2+4f/8f^2-1=0

We multiply all the terms by the denominator


6f+4f-1*8f^2=0

We add all the numbers together, and all the variables

10f-1*8f^2=0

Wy multiply elements

-8f^2+10f=0

a = -8; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-8)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-8}=\frac{-20}{-16}
=1+1/4
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-8}=\frac{0}{-16}
=0
$