3/4f+5=11

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Solution for 3/4f+5=11 equation: 



3/4f+5=11

We move all terms to the left:

3/4f+5-(11)=0



Domain of the equation: 4f!=0

f!=0/4

f!=0

f∈R



We add all the numbers together, and all the variables

3/4f-6=0

We multiply all the terms by the denominator


-6*4f+3=0

Wy multiply elements

-24f+3=0

We move all terms containing f to the left, all other terms to the right

-24f=-3

f=-3/-24

f=1/8

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