3/4h+16=2-1/8h

Solution for 3/4h+16=2-1/8h equation:

3/4h+16=2-1/8h

We move all terms to the left:

3/4h+16-(2-1/8h)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



Domain of the equation: 8h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

3/4h-(-1/8h+2)+16=0

We get rid of parentheses

3/4h+1/8h-2+16=0

We calculate fractions


24h/32h^2+4h/32h^2-2+16=0

We add all the numbers together, and all the variables

24h/32h^2+4h/32h^2+14=0

We multiply all the terms by the denominator


24h+4h+14*32h^2=0

We add all the numbers together, and all the variables

28h+14*32h^2=0

Wy multiply elements

448h^2+28h=0

a = 448; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·448·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*448}=\frac{-56}{896}
=-1/16
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*448}=\frac{0}{896}
=0
$