3/4h-18=12

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Solution for 3/4h-18=12 equation: 



3/4h-18=12

We move all terms to the left:

3/4h-18-(12)=0



Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



We add all the numbers together, and all the variables

3/4h-30=0

We multiply all the terms by the denominator


-30*4h+3=0

Wy multiply elements

-120h+3=0

We move all terms containing h to the left, all other terms to the right

-120h=-3

h=-3/-120

h=1/40

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