3/4k+1/5k=k-2/5

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Solution for 3/4k+1/5k=k-2/5 equation:



3/4k+1/5k=k-2/5
We move all terms to the left:
3/4k+1/5k-(k-2/5)=0
Domain of the equation: 4k!=0
k!=0/4
k!=0
k∈R
Domain of the equation: 5k!=0
k!=0/5
k!=0
k∈R
We add all the numbers together, and all the variables
3/4k+1/5k-(+k-2/5)=0
We get rid of parentheses
3/4k+1/5k-k+2/5=0
We calculate fractions
-k+375k/500k^2+4k/500k^2+8k/500k^2=0
We add all the numbers together, and all the variables
-1k+375k/500k^2+4k/500k^2+8k/500k^2=0
We multiply all the terms by the denominator
-1k*500k^2+375k+4k+8k=0
We add all the numbers together, and all the variables
387k-1k*500k^2=0
Wy multiply elements
-500k^3+387k=0
We do not support ekpression: k^3

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