3/4k+1/8=3/4(k+8)

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Solution for 3/4k+1/8=3/4(k+8) equation: 



3/4k+1/8=3/4(k+8)

We move all terms to the left:

3/4k+1/8-(3/4(k+8))=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R





Domain of the equation: 4(k+8))!=0

k∈R



We calculate fractions


(96kk/(128k^2k+(-(3*4k*8)/(128k^2k+64k^2/(128k^2k=0

We can not solve this equation

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