3/4k+3/8k=12

Solution for 3/4k+3/8k=12 equation:

3/4k+3/8k=12

We move all terms to the left:

3/4k+3/8k-(12)=0


Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R



Domain of the equation: 8k!=0

k!=0/8

k!=0

k∈R


We calculate fractions


24k/32k^2+12k/32k^2-12=0

We multiply all the terms by the denominator


24k+12k-12*32k^2=0

We add all the numbers together, and all the variables

36k-12*32k^2=0

Wy multiply elements

-384k^2+36k=0

a = -384; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-384)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-384}=\frac{-72}{-768}
=3/32
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-384}=\frac{0}{-768}
=0
$