3/4k-(k+1/3)=1/12(k+3)

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Solution for 3/4k-(k+1/3)=1/12(k+3) equation: 



3/4k-(k+1/3)=1/12(k+3)

We move all terms to the left:

3/4k-(k+1/3)-(1/12(k+3))=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R





Domain of the equation: 12(k+3))!=0

k∈R



We add all the numbers together, and all the variables

3/4k-(+k+1/3)-(1/12(k+3))=0

We get rid of parentheses

3/4k-k-(1/12(k+3))-1/3=0

We calculate fractions


(108kk/(144k^2k+(-(1*4k*3)/(144k^2k+(-48k^2)/(144k^2k-k=0

We can not solve this equation

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