3/4k-(k+1/4)=1/16(k+4)

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Solution for 3/4k-(k+1/4)=1/16(k+4) equation: 


k in (-oo:+oo)

(3/4)*k-k-(1/4) = (1/16)*(k+4) // - (1/16)*(k+4)

(3/4)*k-((1/16)*(k+4))-k-(1/4) = 0

(-1/16)*(k+4)+(3/4)*k-k-1/4 = 0

(3*k)/4-1/16*(k+4)-k-1/4 = 0

(-1/16*4*(k+4))/4+(3*k)/4+(4*(-k))/4-1/4 = 0

3*k-1/16*4*(k+4)+4*(-k)-1 = 0

11/4*k-4*k-1-1 = 0

-5/4*k-1-1 = 0

-5/4*k-2 = 0

(-5/4*k-2)/4 = 0

(-5/4*k-2)/4 = 0 // * 4

-5/4*k-2 = 0

-5/4*k-2 = 0 // + 2

-5/4*k = 2 // : -5/4

k = 2/(-5/4)

k = -8/5

k = -8/5

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