3/4k-(k+1/5)=1/20(k+4)

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Solution for 3/4k-(k+1/5)=1/20(k+4) equation: 


k in (-oo:+oo)

(3/4)*k-k-(1/5) = (1/20)*(k+4) // - (1/20)*(k+4)

(3/4)*k-((1/20)*(k+4))-k-(1/5) = 0

(-1/20)*(k+4)+(3/4)*k-k-1/5 = 0

(3*k)/4-1/20*(k+4)-k-1/5 = 0

(-1/20*4*5*(k+4))/(4*5)+(3*5*k)/(4*5)+(4*5*(-k))/(4*5)+(-1*4)/(4*5) = 0

3*5*k-1/20*4*5*(k+4)+4*5*(-k)-1*4 = 0

14*k-20*k-4-4 = 0

-6*k-4-4 = 0

-6*k-8 = 0

(-6*k-8)/(4*5) = 0

(-6*k-8)/(4*5) = 0 // * 4*5

-6*k-8 = 0

-6*k-8 = 0 // + 8

-6*k = 8 // : -6

k = 8/(-6)

k = -4/3

k = -4/3

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