3/4k-12=36

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Solution for 3/4k-12=36 equation: 



3/4k-12=36

We move all terms to the left:

3/4k-12-(36)=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R



We add all the numbers together, and all the variables

3/4k-48=0

We multiply all the terms by the denominator


-48*4k+3=0

Wy multiply elements

-192k+3=0

We move all terms containing k to the left, all other terms to the right

-192k=-3

k=-3/-192

k=1/64

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