3/4m+1/8-9/10m=8

Solution for 3/4m+1/8-9/10m=8 equation:

3/4m+1/8-9/10m=8

We move all terms to the left:

3/4m+1/8-9/10m-(8)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 10m!=0

m!=0/10

m!=0

m∈R


determiningTheFunctionDomain
3/4m-9/10m-8+1/8=0

We calculate fractions


40m^2/2560m^2+1920m/2560m^2+(-2304m)/2560m^2-8=0

We multiply all the terms by the denominator


40m^2+1920m+(-2304m)-8*2560m^2=0

Wy multiply elements

40m^2-20480m^2+1920m+(-2304m)=0

We get rid of parentheses

40m^2-20480m^2+1920m-2304m=0

We add all the numbers together, and all the variables

-20440m^2-384m=0

a = -20440; b = -384; c = 0;
Δ = b2-4ac
Δ = -3842-4·(-20440)·0
Δ = 147456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{147456}=384$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-384)-384}{2*-20440}=\frac{0}{-40880}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-384)+384}{2*-20440}=\frac{768}{-40880}
=-48/2555
$