3/4m+1/8m-6=16

Solution for 3/4m+1/8m-6=16 equation:

3/4m+1/8m-6=16

We move all terms to the left:

3/4m+1/8m-6-(16)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 8m!=0

m!=0/8

m!=0

m∈R


We add all the numbers together, and all the variables

3/4m+1/8m-22=0

We calculate fractions


24m/32m^2+4m/32m^2-22=0

We multiply all the terms by the denominator


24m+4m-22*32m^2=0

We add all the numbers together, and all the variables

28m-22*32m^2=0

Wy multiply elements

-704m^2+28m=0

a = -704; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-704)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-704}=\frac{-56}{-1408}
=7/176
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-704}=\frac{0}{-1408}
=0
$