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3/4m-5-1/2m=12
We move all terms to the left:
3/4m-5-1/2m-(12)=0
Domain of the equation: 4m!=0
m!=0/4
m!=0
m∈R
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
3/4m-1/2m-17=0
We calculate fractions
6m/8m^2+(-4m)/8m^2-17=0
We multiply all the terms by the denominator
6m+(-4m)-17*8m^2=0
Wy multiply elements
-136m^2+6m+(-4m)=0
We get rid of parentheses
-136m^2+6m-4m=0
We add all the numbers together, and all the variables
-136m^2+2m=0
a = -136; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-136)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-136}=\frac{-4}{-272} =1/68 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-136}=\frac{0}{-272} =0 $
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