3/4m=18-2/7m

Solution for 3/4m=18-2/7m equation:

3/4m=18-2/7m

We move all terms to the left:

3/4m-(18-2/7m)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 7m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

3/4m-(-2/7m+18)=0

We get rid of parentheses

3/4m+2/7m-18=0

We calculate fractions


21m/28m^2+8m/28m^2-18=0

We multiply all the terms by the denominator


21m+8m-18*28m^2=0

We add all the numbers together, and all the variables

29m-18*28m^2=0

Wy multiply elements

-504m^2+29m=0

a = -504; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-504)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-504}=\frac{-58}{-1008}
=29/504
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-504}=\frac{0}{-1008}
=0
$