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3/4n+1/8=3/4(n+8)
We move all terms to the left:
3/4n+1/8-(3/4(n+8))=0
Domain of the equation: 4n!=0
n!=0/4
n!=0
n∈R
Domain of the equation: 4(n+8))!=0We calculate fractions
n∈R
(96nn/(128n^2n+(-(3*4n*8)/(128n^2n+64n^2/(128n^2n=0
We can not solve this equation
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