3/4n-1/2n=8

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Solution for 3/4n-1/2n=8 equation:



3/4n-1/2n=8
We move all terms to the left:
3/4n-1/2n-(8)=0
Domain of the equation: 4n!=0
n!=0/4
n!=0
n∈R
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
We calculate fractions
6n/8n^2+(-4n)/8n^2-8=0
We multiply all the terms by the denominator
6n+(-4n)-8*8n^2=0
Wy multiply elements
-64n^2+6n+(-4n)=0
We get rid of parentheses
-64n^2+6n-4n=0
We add all the numbers together, and all the variables
-64n^2+2n=0
a = -64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-64)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-64}=\frac{-4}{-128} =1/32 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-64}=\frac{0}{-128} =0 $

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