3/4p-4/5=2/3p-1

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Solution for 3/4p-4/5=2/3p-1 equation:



3/4p-4/5=2/3p-1
We move all terms to the left:
3/4p-4/5-(2/3p-1)=0
Domain of the equation: 4p!=0
p!=0/4
p!=0
p∈R
Domain of the equation: 3p-1)!=0
p∈R
We get rid of parentheses
3/4p-2/3p+1-4/5=0
We calculate fractions
(-144p^2)/300p^2+225p/300p^2+(-200p)/300p^2+1=0
We multiply all the terms by the denominator
(-144p^2)+225p+(-200p)+1*300p^2=0
Wy multiply elements
(-144p^2)+300p^2+225p+(-200p)=0
We get rid of parentheses
-144p^2+300p^2+225p-200p=0
We add all the numbers together, and all the variables
156p^2+25p=0
a = 156; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·156·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*156}=\frac{-50}{312} =-25/156 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*156}=\frac{0}{312} =0 $

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