3/4q=24q=

Solution for 3/4q=24q= equation:

3/4q=24q=

We move all terms to the left:

3/4q-(24q)=0


Domain of the equation: 4q!=0

q!=0/4

q!=0

q∈R


We add all the numbers together, and all the variables

-24q+3/4q=0

We multiply all the terms by the denominator


-24q*4q+3=0

Wy multiply elements

-96q^2+3=0

a = -96; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-96)·3
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*-96}=\frac{0-24\sqrt{2}}{-192}
=-\frac{24\sqrt{2}}{-192}
=-\frac{\sqrt{2}}{-8}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*-96}=\frac{0+24\sqrt{2}}{-192}
=\frac{24\sqrt{2}}{-192}
=\frac{\sqrt{2}}{-8}
$