3/4w=1/2w-4=12

Solution for 3/4w=1/2w-4=12 equation:

3/4w=1/2w-4=12

We move all terms to the left:

3/4w-(1/2w-4)=0


Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R



Domain of the equation: 2w-4)!=0

w∈R


We get rid of parentheses

3/4w-1/2w+4=0

We calculate fractions


6w/8w^2+(-4w)/8w^2+4=0

We multiply all the terms by the denominator


6w+(-4w)+4*8w^2=0

Wy multiply elements

32w^2+6w+(-4w)=0

We get rid of parentheses

32w^2+6w-4w=0

We add all the numbers together, and all the variables

32w^2+2w=0

a = 32; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·32·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*32}=\frac{-4}{64}
=-1/16
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*32}=\frac{0}{64}
=0
$