3/4x+1/2=5/6x

Solution for 3/4x+1/2=5/6x equation:

3/4x+1/2=5/6x

We move all terms to the left:

3/4x+1/2-(5/6x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x-(+5/6x)+1/2=0

We get rid of parentheses

3/4x-5/6x+1/2=0

We calculate fractions


144x^2/96x^2+72x/96x^2+(-80x)/96x^2=0

We multiply all the terms by the denominator


144x^2+72x+(-80x)=0

We get rid of parentheses

144x^2+72x-80x=0

We add all the numbers together, and all the variables

144x^2-8x=0

a = 144; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·144·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*144}=\frac{0}{288}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*144}=\frac{16}{288}
=1/18
$