3/4x+12=4/3x

Solution for 3/4x+12=4/3x equation:

3/4x+12=4/3x

We move all terms to the left:

3/4x+12-(4/3x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x-(+4/3x)+12=0

We get rid of parentheses

3/4x-4/3x+12=0

We calculate fractions


9x/12x^2+(-16x)/12x^2+12=0

We multiply all the terms by the denominator


9x+(-16x)+12*12x^2=0

Wy multiply elements

144x^2+9x+(-16x)=0

We get rid of parentheses

144x^2+9x-16x=0

We add all the numbers together, and all the variables

144x^2-7x=0

a = 144; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·144·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*144}=\frac{0}{288}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*144}=\frac{14}{288}
=7/144
$