3/4x+12=8-1/2x

Solution for 3/4x+12=8-1/2x equation:

3/4x+12=8-1/2x

We move all terms to the left:

3/4x+12-(8-1/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x-(-1/2x+8)+12=0

We get rid of parentheses

3/4x+1/2x-8+12=0

We calculate fractions


6x/8x^2+4x/8x^2-8+12=0

We add all the numbers together, and all the variables

6x/8x^2+4x/8x^2+4=0

We multiply all the terms by the denominator


6x+4x+4*8x^2=0

We add all the numbers together, and all the variables

10x+4*8x^2=0

Wy multiply elements

32x^2+10x=0

a = 32; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·32·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*32}=\frac{-20}{64}
=-5/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*32}=\frac{0}{64}
=0
$