3/4x+18-x+4=8

Solution for 3/4x+18-x+4=8 equation:

3/4x+18-x+4=8

We move all terms to the left:

3/4x+18-x+4-(8)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+3/4x+14=0

We multiply all the terms by the denominator


-1x*4x+14*4x+3=0

Wy multiply elements

-4x^2+56x+3=0

a = -4; b = 56; c = +3;
Δ = b2-4ac
Δ = 562-4·(-4)·3
Δ = 3184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3184}=\sqrt{16*199}=\sqrt{16}*\sqrt{199}=4\sqrt{199}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{199}}{2*-4}=\frac{-56-4\sqrt{199}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{199}}{2*-4}=\frac{-56+4\sqrt{199}}{-8}
$