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3/4x+2=4x
We move all terms to the left:
3/4x+2-(4x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-4x+3/4x+2=0
We multiply all the terms by the denominator
-4x*4x+2*4x+3=0
Wy multiply elements
-16x^2+8x+3=0
a = -16; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·(-16)·3
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*-16}=\frac{-24}{-32} =3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*-16}=\frac{8}{-32} =-1/4 $
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