3/4x+2=5/2x-6

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Solution for 3/4x+2=5/2x-6 equation:



3/4x+2=5/2x-6
We move all terms to the left:
3/4x+2-(5/2x-6)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x-6)!=0
x∈R
We get rid of parentheses
3/4x-5/2x+6+2=0
We calculate fractions
6x/8x^2+(-20x)/8x^2+6+2=0
We add all the numbers together, and all the variables
6x/8x^2+(-20x)/8x^2+8=0
We multiply all the terms by the denominator
6x+(-20x)+8*8x^2=0
Wy multiply elements
64x^2+6x+(-20x)=0
We get rid of parentheses
64x^2+6x-20x=0
We add all the numbers together, and all the variables
64x^2-14x=0
a = 64; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·64·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*64}=\frac{0}{128} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*64}=\frac{28}{128} =7/32 $

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