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3/4x+2=71/3x
We move all terms to the left:
3/4x+2-(71/3x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(+71/3x)+2=0
We get rid of parentheses
3/4x-71/3x+2=0
We calculate fractions
9x/12x^2+(-284x)/12x^2+2=0
We multiply all the terms by the denominator
9x+(-284x)+2*12x^2=0
Wy multiply elements
24x^2+9x+(-284x)=0
We get rid of parentheses
24x^2+9x-284x=0
We add all the numbers together, and all the variables
24x^2-275x=0
a = 24; b = -275; c = 0;
Δ = b2-4ac
Δ = -2752-4·24·0
Δ = 75625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{75625}=275$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-275}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+275}{2*24}=\frac{550}{48} =11+11/24 $
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