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3/4x+2=x-3
We move all terms to the left:
3/4x+2-(x-3)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-x+3+2=0
We multiply all the terms by the denominator
-x*4x+3*4x+2*4x+3=0
Wy multiply elements
-4x^2+12x+8x+3=0
We add all the numbers together, and all the variables
-4x^2+20x+3=0
a = -4; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·(-4)·3
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8\sqrt{7}}{2*-4}=\frac{-20-8\sqrt{7}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8\sqrt{7}}{2*-4}=\frac{-20+8\sqrt{7}}{-8} $
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