3/4x+2x=5

Solution for 3/4x+2x=5 equation:

3/4x+2x=5

We move all terms to the left:

3/4x+2x-(5)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

2x+3/4x-5=0

We multiply all the terms by the denominator


2x*4x-5*4x+3=0

Wy multiply elements

8x^2-20x+3=0

a = 8; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·8·3
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{19}}{2*8}=\frac{20-4\sqrt{19}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{19}}{2*8}=\frac{20+4\sqrt{19}}{16}
$