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3/4x+4/12x=-12
We move all terms to the left:
3/4x+4/12x-(-12)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 12x!=0We add all the numbers together, and all the variables
x!=0/12
x!=0
x∈R
3/4x+4/12x+12=0
We calculate fractions
36x/48x^2+16x/48x^2+12=0
We multiply all the terms by the denominator
36x+16x+12*48x^2=0
We add all the numbers together, and all the variables
52x+12*48x^2=0
Wy multiply elements
576x^2+52x=0
a = 576; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·576·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*576}=\frac{-104}{1152} =-13/144 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*576}=\frac{0}{1152} =0 $
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