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3/4x-1/2=-1+5/6x
We move all terms to the left:
3/4x-1/2-(-1+5/6x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(5/6x-1)-1/2=0
We get rid of parentheses
3/4x-5/6x+1-1/2=0
We calculate fractions
(-144x^2)/96x^2+72x/96x^2+(-80x)/96x^2+1=0
We multiply all the terms by the denominator
(-144x^2)+72x+(-80x)+1*96x^2=0
Wy multiply elements
(-144x^2)+96x^2+72x+(-80x)=0
We get rid of parentheses
-144x^2+96x^2+72x-80x=0
We add all the numbers together, and all the variables
-48x^2-8x=0
a = -48; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-48)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-48}=\frac{0}{-96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-48}=\frac{16}{-96} =-1/6 $
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