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3/4x-1/2=2/5x+3
We move all terms to the left:
3/4x-1/2-(2/5x+3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x+3)!=0We get rid of parentheses
x∈R
3/4x-2/5x-3-1/2=0
We calculate fractions
(-100x^2)/80x^2+60x/80x^2+(-32x)/80x^2-3=0
We multiply all the terms by the denominator
(-100x^2)+60x+(-32x)-3*80x^2=0
Wy multiply elements
(-100x^2)-240x^2+60x+(-32x)=0
We get rid of parentheses
-100x^2-240x^2+60x-32x=0
We add all the numbers together, and all the variables
-340x^2+28x=0
a = -340; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-340)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-340}=\frac{-56}{-680} =7/85 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-340}=\frac{0}{-680} =0 $
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