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3/4x-1/2=5/8x
We move all terms to the left:
3/4x-1/2-(5/8x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(+5/8x)-1/2=0
We get rid of parentheses
3/4x-5/8x-1/2=0
We calculate fractions
(-256x^2)/128x^2+96x/128x^2+(-80x)/128x^2=0
We multiply all the terms by the denominator
(-256x^2)+96x+(-80x)=0
We get rid of parentheses
-256x^2+96x-80x=0
We add all the numbers together, and all the variables
-256x^2+16x=0
a = -256; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-256)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-256}=\frac{-32}{-512} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-256}=\frac{0}{-512} =0 $
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