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3/4x-1/3=1/2x+2
We move all terms to the left:
3/4x-1/3-(1/2x+2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+2)!=0We get rid of parentheses
x∈R
3/4x-1/2x-2-1/3=0
We calculate fractions
(-16x^2)/72x^2+54x/72x^2+(-36x)/72x^2-2=0
We multiply all the terms by the denominator
(-16x^2)+54x+(-36x)-2*72x^2=0
Wy multiply elements
(-16x^2)-144x^2+54x+(-36x)=0
We get rid of parentheses
-16x^2-144x^2+54x-36x=0
We add all the numbers together, and all the variables
-160x^2+18x=0
a = -160; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-160)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-160}=\frac{-36}{-320} =9/80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-160}=\frac{0}{-320} =0 $
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