3/4x-12=4+1/2x

Solution for 3/4x-12=4+1/2x equation:

3/4x-12=4+1/2x

We move all terms to the left:

3/4x-12-(4+1/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x-(1/2x+4)-12=0

We get rid of parentheses

3/4x-1/2x-4-12=0

We calculate fractions


6x/8x^2+(-4x)/8x^2-4-12=0

We add all the numbers together, and all the variables

6x/8x^2+(-4x)/8x^2-16=0

We multiply all the terms by the denominator


6x+(-4x)-16*8x^2=0

Wy multiply elements

-128x^2+6x+(-4x)=0

We get rid of parentheses

-128x^2+6x-4x=0

We add all the numbers together, and all the variables

-128x^2+2x=0

a = -128; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-128)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-128}=\frac{-4}{-256}
=1/64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-128}=\frac{0}{-256}
=0
$