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3/4x-16=14-1/2x
We move all terms to the left:
3/4x-16-(14-1/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(-1/2x+14)-16=0
We get rid of parentheses
3/4x+1/2x-14-16=0
We calculate fractions
6x/8x^2+4x/8x^2-14-16=0
We add all the numbers together, and all the variables
6x/8x^2+4x/8x^2-30=0
We multiply all the terms by the denominator
6x+4x-30*8x^2=0
We add all the numbers together, and all the variables
10x-30*8x^2=0
Wy multiply elements
-240x^2+10x=0
a = -240; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-240)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-240}=\frac{-20}{-480} =1/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-240}=\frac{0}{-480} =0 $
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