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3/4x-2(3x+2)=-25
We move all terms to the left:
3/4x-2(3x+2)-(-25)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3/4x-2(3x+2)+25=0
We multiply parentheses
3/4x-6x-4+25=0
We multiply all the terms by the denominator
-6x*4x-4*4x+25*4x+3=0
Wy multiply elements
-24x^2-16x+100x+3=0
We add all the numbers together, and all the variables
-24x^2+84x+3=0
a = -24; b = 84; c = +3;
Δ = b2-4ac
Δ = 842-4·(-24)·3
Δ = 7344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7344}=\sqrt{144*51}=\sqrt{144}*\sqrt{51}=12\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-12\sqrt{51}}{2*-24}=\frac{-84-12\sqrt{51}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+12\sqrt{51}}{2*-24}=\frac{-84+12\sqrt{51}}{-48} $
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